Integrand size = 20, antiderivative size = 61 \[ \int \frac {x^3}{\sqrt {c x^2} (a+b x)} \, dx=-\frac {a x^2}{b^2 \sqrt {c x^2}}+\frac {x^3}{2 b \sqrt {c x^2}}+\frac {a^2 x \log (a+b x)}{b^3 \sqrt {c x^2}} \]
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Time = 0.02 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {15, 45} \[ \int \frac {x^3}{\sqrt {c x^2} (a+b x)} \, dx=\frac {a^2 x \log (a+b x)}{b^3 \sqrt {c x^2}}-\frac {a x^2}{b^2 \sqrt {c x^2}}+\frac {x^3}{2 b \sqrt {c x^2}} \]
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Rule 15
Rule 45
Rubi steps \begin{align*} \text {integral}& = \frac {x \int \frac {x^2}{a+b x} \, dx}{\sqrt {c x^2}} \\ & = \frac {x \int \left (-\frac {a}{b^2}+\frac {x}{b}+\frac {a^2}{b^2 (a+b x)}\right ) \, dx}{\sqrt {c x^2}} \\ & = -\frac {a x^2}{b^2 \sqrt {c x^2}}+\frac {x^3}{2 b \sqrt {c x^2}}+\frac {a^2 x \log (a+b x)}{b^3 \sqrt {c x^2}} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.64 \[ \int \frac {x^3}{\sqrt {c x^2} (a+b x)} \, dx=\frac {x \left (b x (-2 a+b x)+2 a^2 \log (a+b x)\right )}{2 b^3 \sqrt {c x^2}} \]
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Time = 0.13 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.62
method | result | size |
default | \(\frac {x \left (b^{2} x^{2}+2 a^{2} \ln \left (b x +a \right )-2 a b x \right )}{2 \sqrt {c \,x^{2}}\, b^{3}}\) | \(38\) |
risch | \(\frac {x \left (\frac {1}{2} b \,x^{2}-a x \right )}{\sqrt {c \,x^{2}}\, b^{2}}+\frac {a^{2} x \ln \left (b x +a \right )}{b^{3} \sqrt {c \,x^{2}}}\) | \(46\) |
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Time = 0.22 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.69 \[ \int \frac {x^3}{\sqrt {c x^2} (a+b x)} \, dx=\frac {{\left (b^{2} x^{2} - 2 \, a b x + 2 \, a^{2} \log \left (b x + a\right )\right )} \sqrt {c x^{2}}}{2 \, b^{3} c x} \]
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\[ \int \frac {x^3}{\sqrt {c x^2} (a+b x)} \, dx=\int \frac {x^{3}}{\sqrt {c x^{2}} \left (a + b x\right )}\, dx \]
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Time = 0.23 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.64 \[ \int \frac {x^3}{\sqrt {c x^2} (a+b x)} \, dx=\frac {x^{2}}{2 \, b \sqrt {c}} + \frac {\left (-1\right )^{\frac {2 \, a c x}{b}} a^{2} \log \left (-\frac {2 \, a c x}{b {\left | b x + a \right |}}\right )}{b^{3} \sqrt {c}} + \frac {2 \, a x}{b^{2} \sqrt {c}} + \frac {a^{2} \log \left (b x\right )}{b^{3} \sqrt {c}} - \frac {3 \, \sqrt {c x^{2}} a}{b^{2} c} + \frac {3 \, a^{2}}{2 \, b^{3} \sqrt {c}} \]
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Time = 0.32 (sec) , antiderivative size = 66, normalized size of antiderivative = 1.08 \[ \int \frac {x^3}{\sqrt {c x^2} (a+b x)} \, dx=-\frac {a^{2} \log \left ({\left | a \right |}\right ) \mathrm {sgn}\left (x\right )}{b^{3} \sqrt {c}} + \frac {a^{2} \log \left ({\left | b x + a \right |}\right )}{b^{3} \sqrt {c} \mathrm {sgn}\left (x\right )} + \frac {b \sqrt {c} x^{2} \mathrm {sgn}\left (x\right ) - 2 \, a \sqrt {c} x \mathrm {sgn}\left (x\right )}{2 \, b^{2} c} \]
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Timed out. \[ \int \frac {x^3}{\sqrt {c x^2} (a+b x)} \, dx=\int \frac {x^3}{\sqrt {c\,x^2}\,\left (a+b\,x\right )} \,d x \]
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